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On Fri, 9 Jul 1999 10:06:48 +0200, Stefan Hundenborn wrote: >select partyname, count(*) as anzahl from partybase >group by partyname >having anzahl > 1 Ohje, so einfach wars! thnx amalesh -- Keep Agent alive: http://www.living-source.com/agent/ LS at CCC-Camp : http://www.living-source.com/ccc/ German Goatrance: http://www.goatrance.de Contact : ak_(at)_living-source.com ~ icq:963380
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