[php] Zeitabfrage

[Sebastian Mendel]

Sebastian Mendel wrote:

> $days = 0;
> $month = 0;
> $years = 0;
> 
> $start = strtotime('2004-05-12');
> $end = strtotime('2005-06-12');
> 
> $days = date('d', $end) - date('d', $start);
> if ( $days < 0 )
> {
>   $month--;
>   $days = date('t', $start) - date('d', $start);
>   $days += date('d', $end);
> }
> 
> $month += date('n', $end) - date('n', $start);
> if ( $month < 0 )
> {
>   $years--;
>   $month = 11;
     $month -= 12; // naja, kleiner tipp-fehler! ;-)
> }
> 
> $years += date('y', $end) - date('y', $start);
> 
> echo $years . ' Jahr(e) ' . $month . ' Monat(e) und ' . $days . ' Tag(e).';


-- 
Sebastian Mendel (www.sebastianmendel.de)

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