[php] noch eine Frage zu preg_replace

[Daniel Beulshausen]

At 13:05 04.05.2001 +0200, Gregor Wolf wrote:

>>$str =3D "Eine Seite im <b> Internet </b> www.php3.com";
>>$str =3D=
 preg_replace("!<b>(.+)<\/b>!","<b>".strtoupper("\\1")."</b>",$str);
>>                                                       ^^^^^ ??????
>Description
>
>( http://www.php.net/manual/en/function.preg-replace.php )
>
>mixed preg_replace (mixed pattern, mixed replacement, mixed subject [, int=
=20
>limit])
>
>Searches subject for matches to pattern and replaces them with=20
>replacement. If limit is specified, then only limit matches will be=20
>replaced; if limit is omitted or is -1, then all matches are replaced
>
>
>"!<b>(.+)<\/b>!" kann ja nicht gefunden und replaced werden, versuch mal :
>"<b>(.+)<\/b>"

m=FCll...
folgendes sollte helfen:
<?php
  $string =3D "blabla <b>internet</b> blabla";
  print=
 preg_replace("/(<b>.+(?=3D<\/b>)<\/b>)/es","strtoupper('\\1')",$string);
?>

daniel

/*--
daniel beulshausen - daniel_(at)_php4win.de
using php on windows? http://www.php4win.de