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Markus Dobel wrote: > SELECT COUNT(DISTINCT MasterID) FROM All_Reports; > SELECT COUNT(DISTINCT MasterID FROM All_Reports); http://www.tcx.se/Manual_chapter/manual_Reference.html#Group_by_functions COUNT(DISTINCT expr,[expr...]) Returns a count of the number of different values. mysql> select COUNT(DISTINCT results) from student; In MySQL you can get the number of distinct expressions combinations by giving a list of expressions. In ANSI SQL you would have to do a concatenation of all expressions inside CODE(DISTINCT ..). --- Was sagt denn "SELECT VERSION() as v" bei Dir? Kristian -- Kristian Köhntopp, NetUSE Kommunikationstechnologie GmbH Siemenswall, D-24107 Kiel, Germany, +49 431 386 436 00 Using PHP3? See our web development library at http://phplib.netuse.de/ (We have moved! Update your bookmarks!)
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