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Hi,
* Bjoern Schmidt wrote:
> $link = mysql_connect("127.0.0.1","gb_user","");
Danach:
mysql_select_db( "guestbook" ); // "guestbook",$link);
$query = "SELECT name FROM eintraege WHERE id=1";
if ( $res = mysql_query( $query ) )
{
if ( mysql_num_rows( $res ) > 0 )
{
$name = mysql_result( $res,0 );
/* oder:
*
* $row = mysql_fetch_array( $res );
*
* $name = $row["name"];
*
*/
print "Name ist $name<br>\n";
} else
{
print "Es existiert kein Datensatz mit der ID 1";
}
} else
{
print "MySQL-Fehler: ".mysql_error()."<br>\n";
}
HTH, Björn.
--
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var $url="http://www.rent-a-phpwizard.de/";
var $fon="0931/7843792"; var $fax="0931/7843795";
} ?> /* Björn Schotte, "Mr. PHP" */
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